Question

if x-1 is factor of polynomial x³-kx²+19x-12 then value of k is​

Answer 1

Answer:

k=8 should be right answer

Answer 2

if x-1 is factor then f(x) = x³-kx²+19x-12

x-1 = 0 so x = 1

f(1) = 0

(1)³-k(1)²+19(1) -12 =0

1 - k+ 19 -12 = 0

1 +19 -12. =k

20 - 12 = k

8 = k

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