If x=1 is the common root of ax2+bx+2=0 and x2+x+b=0 then ab=
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Given that
x = 1
ax²+bx+2 = 0
put the value of x = 1
a×(1)²+b×1+2 = 0
a+b = -2 ...............(i)
x²+x+b = 0
put x = 1
(1)²+1+b = 0
1+1+b = 0
b = -2 .........(ii)
put the value of b = -2 in eq.(i)
a+b = -2
a+(-2) = -2
a = -2+2
a = 0
ab = ab
ab = 0×(-2)
ab = 0
Hence, the value of ab is zero
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