if (x-1) is the factor of a^2x^3-4ax+4a-1 find a
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6
the value of a is +1 or -1
yashas5:
how i did not understand
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19
put x = 1
a^2×1^3-4a×1+4a-1 = 0
a^8-4a+4a-1
a^8 = 1
hence a = 1 or -1
a^2×1^3-4a×1+4a-1 = 0
a^8-4a+4a-1
a^8 = 1
hence a = 1 or -1
i did not understand how did x^2 become x^8
antuall ot is x^2^3 which is equal to x^8
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