Question

If (x+1) is the factor of the polynomial [(x^2)+(3x)+m)] , then find the value of m.​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Given (x+1) is the zero of p(x)=x^2+3x+m

since, x+1=0

= x = -1

p(-1) = (-1)^2+(3×-1)+m = 0

p(-1) = 1+(-3)+m = 0

p(-1) = 1-3+m = 0

p(-1) = -2+m = 0

therefore, 【 m = 2 】