if x+1 is the factor of the popynomial 2x square + kx. find the value of k
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Answered by
3
Hlo friend.. Nice question
Here is ur answer :
p(x) = 2x² + kx.
g(x) = x + 1
x= - 1
p(x) = 0
P(-1)= 2 (-1)²+ k(-1) = 0
2- k = 0
-k = -2
k = 2
HOPE IT HELPS YOU...
REGARDS
@sunita
Here is ur answer :
p(x) = 2x² + kx.
g(x) = x + 1
x= - 1
p(x) = 0
P(-1)= 2 (-1)²+ k(-1) = 0
2- k = 0
-k = -2
k = 2
HOPE IT HELPS YOU...
REGARDS
@sunita
thesarcasticsoul:
i'm sorry but its x^2 so the answer is 2
Answered by
0
According to factor theorem,
If the factor is x+a, then P(-a) =0
=>P(-1)=2(-1)^2+k(-1)=0
=>P(-1)= 2-k=0
=>P(-1)=k=0+2
=>k=2
Hope this helped you :)
If the factor is x+a, then P(-a) =0
=>P(-1)=2(-1)^2+k(-1)=0
=>P(-1)= 2-k=0
=>P(-1)=k=0+2
=>k=2
Hope this helped you :)
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