Question

If x = 1 is the root of the equation x^3 -2x^2- 5x +6, find the other roots

Answer 1

Answer:

Step by step solution :

STEP 1:

Equation at the end of step 1

(((x3) + 3x2) - 5x) - 6 = 0

STEP 2:

Checking for a perfect cube

2.1 x3+3x2-5x-6 is not a perfect cube

Trying to factor by pulling out :

2.2 Factoring: x3+3x2-5x-6

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1: -5x-6

Group 2: x3+3x2

Pull out from each group separately :

Group 1: (5x+6) • (-1)

Group 2: (x+3) • (x2)

Equation at the end of step 2:

x3 + 3x2 - 5x - 6 = 0

STEP 3:

Cubic Equations:

3.1 Solve x3+3x2-5x-6 = 0

Future releases of Tiger-Algebra will solve equations of the third degree directly.

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Answer 2

Roots of f(x),

X = 1, -2, 3

refer to the attachment