Question

if (X+1) is the zero of px3+2x2+5x+4 then find p​

Answer 1

Step-by-step explanation:

x+1=0. x=(-1). p(x)=px³+2x²+ 5x+4=0. p(-1)=p(-1)³+2(-1)²+5(-1)+4=0. -p+2-5 +4=0. p=4-3. p=1