If x-1 is the zero of the polynomial () = 4 − 12 then find k
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here is your answer
f(x)=x^3 - 2x^2+4x+k
put x = 1(as it is a zero it will make equation equal to zero)
f(1)=1^3-2(1)^2+4(1)+k=0
therefore:
1-2+4+K=0
-1+4+K=0
3+K=0
K= -3
I hope it helps
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