Question

If x_1 isa factor of x2_2kx+1 then the value of k

Answer 1

Step-by-step explanation:

If, x-1

then p(x)

p(1)

p(1)=1^2-2×1k+1 ... ( By factor theorem)

p(1)= 1-2k+1

p(1)=2-2k

If ,

x-1 is a factor of x^2-2xk+1

then,

p(1)=0

0= 2-2k

2k=2

k=1

Answer 2

As (x-1) is a factor of x^2 - 2kx + 1

Hence, we put x=1 in the given equation

x^2 - 2kx + 1 = 0

1^2 - 2k*1 + 1 = 0

1 -2k + 1 = 0

2 - 2k = 0

2k = 2

k = 2/2

k = 1