Question

If x=1+logbc to base a , y=1+logac to base c ,z=1+logac to base b then prove that 1/x+1/y+1/z=1

Answer 1

Answer:

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Answer 2

Answer:

Step-by-step explanation:

x = 1+ log a bc =loga a+ loga bc

= loga abc

therefore 1/x=logabc a

similarly y = log b abc

z= log c abc

(xy +yz+ zx)/xyz

= 1/z + 1/x +1/y

= logabc c +logabc a +logabc b

= log abc abc

=1

(xy +yz+ zx)/xyz = 1

Hope it helps you...