if x^1-logxbase5=0.04 then x=
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For log(x−1) to be defined, x>1
We have,
log
0.04
(x−1)≥log
0.2
(x−1),
⇒
log0.04
log(x−1)
≥
log0.2
log(x−1)
,[∵log
b
a=
logb
loga
]
⇒
−log25
log(x−1)
≥
−log5
log(x−1)
⇒
−2log5
log(x−1)
≥
−log5
log(x−1)
⇒log(x−1)≤2log(x−1)
⇒x−1≤(x−1)
2
⇒(x−1)
2
(x−2)≤0
Therefore, x≥2
Step-by-step explanation:
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