Question

If x+1 men will do the work in x+1 days, find the number of days that x+2 men can finish the same work.

Answer 1

We know that,

x+1 men ⇒x+1 days

1 man ⇒(x+1)∗(x+1) days

x+2 men ⇒x+2(x+1)2 days

∴,x+2 men can do the same work in (x+2)(x+1)2 days

Answer 2

Answer:

QUESTION:

If x+1 men will do the work in x+1 days, find the number of days that x+2 men can finish the same work.

Let's assume:

Number of people=x+1

Number of days=x+1

SOLUTION:

Total people= people×days

Total people=(x+1)(x+1)

people available=x+2

Number of days:

$= \frac{(x + 1)(x + 1)}{x + 2}$

$= \frac{(x + 1) {}^{2} }{x + 2}$

Therefore, Number of days are

$\frac{(x + 1)(x + 1)}{x + 2}$

Hope it helps you:)