Question

if x+1 over x = 9, the. find the value of x cube + 1 over x cube
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Answer 1

Step-by-step explanation:

x + 1 / x = 9

x + 1 = 9x

9x - x = 1

8x = 1

x = 1/ 8

x^ 3 + 1 / x^ 3 = (1/8)^ 3 + 1

(1/8)^ 3

= 1/ 512 + 1

1/ 512

= 1 + 512 / 512

1/ 512

= 1 + 512

= 513

therefore, the value of x cube + 1 over x cube is 513.

Answer 2

Answer:

Given that,

$\frac{x + 1}{x} = 9$

=>$x + 1 = 9x$

=>$8x = 1$

=>$x = \frac{1}{8}$

To Find:

$\frac{ {x}^{3} + 1}{ {x}^{3} }$

On substituting "x=1/8" ...

=>$\frac{ (\frac{1}{8}) ^{3} + 1}{( \frac{1}{8} ) ^{3} }$

=> $(\frac{1}{512} + 1) \div ( \frac{1}{512} )$

=>$\frac{513}{512} \times 512$

=> $513$

Therefore, the value of the given expression is "513"