Question

If x^1/p=y^1/q=z^1/r and xyz=1 then the valie of p+q+r is

Answer 1

Hi Mate !!!

x^ ( 1 / p ) = y^ ( 1 / q )

=>. x = y^ ( p / q ) ..... equation 1

,

y^ ( 1 / q ) = z^ ( 1 / r )

=>. y = z^ ( q / r ) ...... equation 2

Now, put value of y in equation 1

x = z^ ( p / r )

xyz = 1. given

=>. z^ ( p / r ) × z^ ( q / r ) × z = 1

=>. z^[ { ( p / r ) +( q / r ) +1 }] = z^ ( 0 ).
because z^ ( 0 ) = 1

=>. ( p / r ) + ( q / r ) + 1 = 0

=>. p + q + r = 0

Have a nyc tym