Math, asked by chyshweta8, 2 months ago

if x=1- root 2 find the value of x+ 1​

Answers

Answered by samalbishnu001
0

Answer:

x=1-√2

adding 1 both sides

x+1=1-√2+1

x+1=2-√2

x+1=√2(√2-1)

Answered by luckysampu11
0

Step-by-step explanation:

Given x=1 - √2 - - - (1)1

1\x = 1/1-√2

=1+√2/(1-√2)(1+√2)

=1+√2)^2

= - (1+√2) - - (2)

NOW

(x-1/x)^3

= ( 1 - 1/x)

=(1-√2 - [-(1+√2)])^3

=(1-√2+1+√2)^3

=2^3

=8

Therefore,

x-1/x)^3=8

answer = 8

Similar questions