if x=1- root 2 find the value of x+ 1
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Answered by
0
Answer:
x=1-√2
adding 1 both sides
x+1=1-√2+1
x+1=2-√2
x+1=√2(√2-1)
Answered by
0
Step-by-step explanation:
Given x=1 - √2 - - - (1)1
1\x = 1/1-√2
=1+√2/(1-√2)(1+√2)
=1+√2)^2
= - (1+√2) - - (2)
NOW
(x-1/x)^3
= ( 1 - 1/x)
=(1-√2 - [-(1+√2)])^3
=(1-√2+1+√2)^3
=2^3
=8
Therefore,
x-1/x)^3=8
answer = 8
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