Math, asked by sunnyaman6106, 9 months ago

If x=1+root2 find x-1/x whole cube

Answers

Answered by biligiri
2

Answer:

given, x = 1+√2

to evaluate x-1/x

first find the reciprocal of x

1/x = 1/(1+√2)

now rationalise the denominator of 1/x

= 1/(1+√2)*(1-√2)(1-√2)

= 1*(1-√2)/(1^2 - (√2)^2)

= (1-√2)/1-2

= (1-√2)/-1

= √2 - 1

now x - 1/x = 1+√2-(√2-1)

= 1+√2-√2+1

= 2

therefore (x-1/x)^3 = (2)^3

. = 8

Answered by ramneetkaur2486
0

Step-by-step explanation:

this is the solution of your question

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