If x=1+root2 find x-1/x whole cube
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given, x = 1+√2
to evaluate x-1/x
first find the reciprocal of x
1/x = 1/(1+√2)
now rationalise the denominator of 1/x
= 1/(1+√2)*(1-√2)(1-√2)
= 1*(1-√2)/(1^2 - (√2)^2)
= (1-√2)/1-2
= (1-√2)/-1
= √2 - 1
now x - 1/x = 1+√2-(√2-1)
= 1+√2-√2+1
= 2
therefore (x-1/x)^3 = (2)^3
. = 8
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