Question

if (x-1)scube =8 find the value of (x+1) whole square​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

${(x + 1)}^{3} = 8$

$=> {(x + 1)}^{3} = {2}^{3}$

$=>x + 1 = 2$

$\bold{x = 1}$

To find,

${(x + 1)}^{2}$

$=>{(1 + 1)}^{2}$

$=> {2}^{2}$

$\boxed{4}$