Question

if x=1/ square root 5-2,then find the value of x^2+1/x^2​

Answer 1

Step-by-step explanation:

$x = \frac{ 1}{ \sqrt{5} - 2 }$

$x = \frac{1( \sqrt{5} + 2) }{( \sqrt{5} - 2)( \sqrt{5} + 2) }$

$x = \frac{ \sqrt{5} - 2 }{ { (\sqrt{5} }^{2}) - {2}^{2} }$

x=√5-2

1/x=√5+2

(x+1/x)=2√5

(x+1/x)²=(2√5)²

x²+1/x²+2(x)(1/x)=20

x²+1/x²+2=20

x²+1/x²=18

Answer 2

Step-by-step explanation:

Please refer to the attachment below

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