Question

If (x-1) to the power 3=8 then find (x+1) to the power 2??

Answer 1

$\red{Question:-}$

If (x-1)³ = 8 then find (x+1)² ?

$\green{Answer:-}$

${\implies}{(x - 1) }^{3} = 8$

${\implies}(x - 1) = \sqrt[3]{8}$

${\implies}x - 1 = 2$

${\implies}x = 2 + 1$

${\implies}x = 3$

Now,

${\implies}{(x+1)}^{2}$

${\implies}{(3+1)}^{2}$

${\implies}{(4)}^{2}$

${\implies}16$

Your answer = (x+1)² = 16

Answer 2

$\red{\color{white}{\fcolorbox{cyan}{black}{Answer:-}}}$

${\implies}{(x - 1) }^{3}$

${\implies}(x - 1) = \sqrt[3]{8}$

${\implies}x - 1 = 2$

${\implies}x = 2 + 1$

${\implies}x = 3$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀

${\implies}{(x+1)}^{2}$

${\implies}{(3+1)}^{2}$

${\implies}{(4)}^{2}$

${\implies}16$

Your answer = (x+1)² = 16