Question

If x= 1 upon 3 - 2 rooot2 find the value of x3 - 5x2 - 11x +7

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

X=1/3-2✓2

x=1/3-2✓2*3+2✓2/3+2✓2

=3+2✓2/(3)^2-(2✓2)^2

3+2✓2/9-8

=3+2✓2

Now x= 3+2✓2

(x-3)^2=(2✓2)^2

x^2+3^2-2*x*3=8

x^2+9-6x=8

x^2+9-8-6x=0

x^2-6x+1=0___eq.1

Now we have to divide the given eq. Of ur question with this value(

x^2-6x+1)

On division we get

Divisor=x+1 and remainder -5x+6

So the given polynomial

x3 - 5x2 - 11x +7=(x+1)(x^2-6x+1)+(-5x+6)

Now as from eq. 1st

x^2-6x+1=0___eq.1

Therefore (x+1)(x^2-6x+1) will become 0.

So x3 - 5x2 - 11x +7=0+(-5x+6)

=-5x+6 is it's answer

Hope it helps

It took me a lot time