Question

if x- 1 upon x = 7 find x^2+1 upon x^2​

Answer 1

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Answer 2

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$\frac{x - 1}{x} = 7 \\ \\ x - 1 = 7x \\ x - 7 x = 1 \\ x = - \frac{1}{6 } \\ \\ \frac{ {x}^{2} + 1}{ {x}^{2} } = \frac{ - { \frac{1}{6} }^{2} + 1}{ - { \frac {1}{6} }^{2} } \\ \\ \frac{ \frac{1}{36} + 1}{ \frac{1}{36} } = \frac{ \frac{37}{36} }{ \frac{1}{36} } \\ \\ = 37$

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