Question

if x - 1 whole square is equal to 8 what is the value of x + 1 whole square

Answer 1

${(x - 1)}^{2} = 8 \\ (x - 1) = 2 \sqrt{2} \\ x = 2 \sqrt{2 } + 1 \\ \\ {(x + 1)}^{2} = {x}^{2} + 1 + 2x \\ = {(2 \sqrt{2} + 1) }^{2} + 1 + 4 \sqrt{2} \\ 8 + 1 + 4 \sqrt{2} + 1 + 4 \sqrt{2} \\ = 10 + 8 \sqrt{2}$
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