Math, asked by aamolia1969, 11 months ago

if x-1/x=1/3 evaluate x³-1/x³​

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Answered by Anonymous
8

 \textit {Here\:is\:your\:Answer}

x -  \frac{1}{x}  = 3 \\ cubeing \: on \: both \: sides \\  \\ (x -  \frac{1}{x} ) {}^{3}  =  \frac{1}{3 {}^{3} }  \\  \\ x {}^{3}  -  \frac{1}{x {}^{3} }  - 3( \frac{1}{x}  \times x)(x -  \frac{1}{x} ) =  \frac{1}{27}  \\ \\  becoz \:  \: (x - y) {}^{3}  = x {}^{3}  - y {}^{3}  - 3xy(x - y) \\  \\ so \\  x {}^{3}  -  \frac{1}{x {}^{3} }  =  \frac{28}{27}

Answered by Anonymous
0

┏━━━━•❅•°•❈ ↯ •°•❅•━━━━┓

here's your answer

┗━━━━•❅•°•❈ ↯ •°•❅•━━━━┛

Lymphocytes ✍

✒They have round shaped nucleus.

Monocytes ✍

✒They have horseshoe shaped or kidney shaped nucleus.

✥Hope it helps❢❢

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