If x-1/x = 1/3 then 9x2 + 9/x2 is equal to
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Step-by-step explanation:
3, 3}
If f : A → B, such that y ∈ B, then
f−1
{ y }={x ∈ A: f (x) = y}.
In other words,
f−1
{ y} is the set of pre-images of y.
Let
f−1
9} = x
Then, f (x) = 9
⇒ x2 = 9
⇒ x = ± 3
∴
f−1
{9} = {- 3, 3}.
.
.
.
mark me as brain3, 3}
If f : A → B, such that y ∈ B, then
f−1
{ y }={x ∈ A: f (x) = y}.
In other words,
f−1
{ y} is the set of pre-images of y.
Let
f−1
9} = x
Then, f (x) = 9
⇒ x2 = 9
⇒ x = ± 3
∴
f−1
{9} = {- 3, 3}.
mark me as brainlist
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