Question

if (x-1),(X+1) & (2x+3) are in A.P., then the value of X is ​

Answer 1

Answer:

(x+1)-(x-1)=(2x+3)-(x+1)

x+1-x+1=2x+3-x-1

2=x+2

x=2-2=0

Answer 2

Given A.P are (x-1),(x+1) & (2x+3)

In an A.P , we know that a2 -a1 = a3 - a2

substituting all these values, we get

(x +1)-(x-1)=(2x+3) - (x+1)

So, we get

x+1-x+1=2x+3-x -1

2=x+2

x = 2-2

So, x = 0

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