Question

if x-1/x= -1, find the value of x^2+1/x^2

Answer 1

Answer:

3

Step-by-step explanation:

in equation we can square both side as per requirement

$x - \frac{1}{x} = - 1$

${(x -\frac{1}{x}}</u><u>)</u><u>^{2}</u><u> </u><u> = { - 1}^{2}$

it is (a-b) whole square

${x}^{2} + \frac{1}{ {x}^{2} } - 2 = 1$

-2*x*1/x will be -2

${x}^{2} + \frac{1}{ {x}^{2} } = 1 + 2 = 3$

by shifting -2 that side, it will become +2

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Answer 2

Answer:

GIVEN ::

x - (1/x) = - 1

Now

x² + (1/x)²

= (x - 1/x)² + 2*x*(1/x)

= (-1)² + 2

= 1 + 2

= 3

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