if x+(1/x)=-1, find x^3
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x+1/x=3 .
Now, x+1= x.3,
Or, x+1=3x,
Or, 2x=1,
Or, x=1/2 ( or .5)
Hence the value of x is 1/5 (0r .5)
solution 2:
By taking the LCM WE GET
X^2+1=3X
X^2–3X+1=0
X=-B±(√B^2–4AC)/2A
HERE B=-3,A=1,C=1
X=3±(√9–4)/2
X=[3+√5]/2,[3-√5]/2
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