Question

if (x-1/x) =10,then find the value of x2+1/x2.​

Answer 1

Answer:

(x-1/x)

$(x - 1 \div x)^{2} = (10)^{2}$

x

${x}^{2} + \frac{1}{x^{2} } - 2 \times x \times \frac{1}{x} = {10}^{2}$

${x}^{2} + \frac{1}{x^{2} } - 2 = 100$

${x}^{2} + \frac{1}{x^{2} } = 100 + 2 = 102$