Math, asked by Dasham10, 1 year ago

If x+ 1/x = 110. Then find x^3 + 1/x^3

Answers

Answered by gaurav2013c
2
x+ 1/x = 110
=> (x+1/x)^2 = 12100
=> x^2 + 1/x^2 +2*x*1/x = 12100
=> x^2 + 1/x^2 + 2 = 12100
=> x^2 + 1/x^2 = 12098 ---------(1)

Now,
x^3 + 1/x^3 = (x+1/x) (x^2 +1/x^2 - x*1/x)
= 110 * (12098 - 1) from equation 1
= 110 * 12097
= 1330670

rohitkumargupta: check your step bri
rohitkumargupta: bro
rohitkumargupta: u write 2 on the place of 1
gaurav2013c: yeah now I got it
rohitkumargupta: hn
gaurav2013c: but I can't edit
rohitkumargupta: ok wait
gaurav2013c: ok
RehanAhmadXLX: Is it correct now?
rohitkumargupta: yes
Answered by rohitkumargupta
7
HELLO DEAR,

GIVEN THAT:-
x + \frac{1}{x} = 110
TAKE CUBE BOTH SIDE

(x + \frac{1}{x} )^{3} = {110}^{3} \\ = > {x}^{3} + ( { \frac{1}{x} })^{3} \times 3x \times \frac{1}{x} (x + \frac{1}{x} ) = 1331000\\ = > {x}^{3} + { \frac{1}{x} }^{3} + 3 \times 110 = 1331000 \\ = > {x}^{3} + ( { \frac{1}{x} })^{3} = 1331000 - 330 \\ = > 1330670
I HOPE ITS HELP YOU DEAR,
THANKS

rohitkumargupta: buy your answer is wrong
rohitkumargupta: bhai
gaurav2013c: I know tell the moderator to delete it
rohitkumargupta: ok
gaurav2013c: hogaya bhai
gaurav2013c: Correct
gaurav2013c: thanks
gaurav2013c: and sorry for mistake
rohitkumargupta: its ok
rohitkumargupta: bhai
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