Question

If x -1/x= 13 , find the value of x^2 + 1/x^2

Answer 1

Answer:

x-1/x=13

(x- 1/x)²=x²+1/x²-2(x)(1/x)

13²=x² +1/x²-2

169=x² +1/x²-2

x²+ 1/x²=169+2=171

therefore, x²+1/x² is 171

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