Question

if [x-1/x]=15 then find the value of [x^2+1/x^2]​

Answer 1

Answer:

$197$

Step-by-step explanation:

$\frac{(x-1)}{x} =15\\\\x-1 =15x\\\\15x-x =-1\\\\14x = -1\\\\x =\frac{-1}{14}$

$\frac{x^2+1}{x^{2} }$

$\frac{(\frac{-1}{14}) ^2+1}{(\frac{-1}{14} )^{2} }$

$\frac{(\frac{1}{196})+1}{(\frac{1}{196} ) }$

$\frac{(\frac{1+196}{196})}{(\frac{1}{196} ) }$

$\frac{(\frac{197}{196})}{(\frac{1}{196} ) }$

$(\frac{197}{196})*{196}$

$197$