Question

if [x+1/x]=16, find the value of x^2+1/x^2​

Answer 1

Step-by-step explanation:

so this question's answer is 254

Answer 2

Answer:

$x + \frac{1}{x} = 16 \\ squaring \: both \: side \: we \: get \\ {(x + \frac{1}{x}) }^{2} = {16}^{2} \\ {x}^{2} + \frac{1}{ {x}^{2} } + 2x \times \frac{1}{x} = 256 \\ {x}^{2} + \frac{1}{ {x}^{2} } + 2 = 256 \\ so \\ {x}^{2} + \frac{1}{ {x}^{2} } =2 56 - 2 = 254$