Question

if (x+1/x)=√17 then what is the value of x^2+1/x^2​

Answer 1

Step-by-step explanation:

both side squaring

$( {x + \frac{1}{x} })^{2} = { \sqrt{17} }^{2}$

${x}^{2} + \frac{1}{ {x}^{2} } + 2 \times x \times \frac{1}{x} = 17$

${x}^{2} + \frac{1}{ {x}^{2} } + 2 = 17$

${x}^{2} + \frac{1}{ {x}^{2} } = 17 - 2$

${x}^{2} + \frac{1}{ {x}^{2} } = 15$

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