if (√x + 1/√x)^2 = 11 find √x^3 + 1/√x^3
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Answer:
Given ⇒
x² + 1/x² = 11
Now, Using the Formula,
(a - 1/a)² = a² + 1/a² - 2
∴ (x - 1/x)² = x² + 1/x² - 2
∴ (x - 1/x)² = 11 - 2
∴ x - 1/x = √9
⇒ x - 1/x = 3
Now,
Using the Formula,
(a - 1/a)³ = a³ - 1/a³ - 3(a - 1/a)
∴ (x - 1/x)³ = x³- 1/x³ - 3(x - 1/x)
∴ (3)³ = x³ - 1/x³ - 3(3)
⇒ 27 = x³ - 1/x³ - 9
⇒ x³ - 1/x³ = 27 + 9
⇒ x³ - 1/x³ = 36
Hence, the value of the x³ - 1/x³ is 36.
Hope it helps.
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