If (x+1/x)^2 = 3 show that (x^3+1/x^3)=0
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Answered by
5
(x+1/x)^2 = 3
x+1/x=root3
cubing on both sides
x^3+1/x^3+3(x+1/x)=3 root 3
x^3+1/x^3+3root 3=3 root 3
x^3+1/x^3 = 0
x+1/x=root3
cubing on both sides
x^3+1/x^3+3(x+1/x)=3 root 3
x^3+1/x^3+3root 3=3 root 3
x^3+1/x^3 = 0
Answered by
3
Answer:
Proved (x^3+1/x^3) = 0
Step-by-step explanation:
(x+1/x) ^2 = 3
x + 1/x = √3
Take a cube both side,
x^3 + 1/x^3 + 3 (x + 1/x) = (√3 )³
x^3 + 1/x^3 + 3 √3 = (√3 )³
x^3+1/x^3 = 3 √3 - 3√3 = 0
(x+1/x)^2 = 3
x + 1/x = √3
Hence proved (x^3+1/x^3) = 0
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