if (x+1/x)^2=3 ,show that x^3+1/x^3=0please give the solution
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Answer:
given (x+1/x)^2=3
(x+1/x)=√3
formula
(x+1/x)^3=x^3+1/x^3+3(x+1/x)
(√3)^3=x^3+1/x^3+3√3
√3*√3*√3=x^3+1/x^3+3√3
3√3=x^3+1/x^3+3√3
=> x^3+1/x^3=0 hence proved..
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