If (x+1/x) ²=3, show that (x³+1/x³) =0
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Given:
★ (x + 1/x)² = 3
To prove:
☞ (x³ + 1/x³) = 0
Identity used:
- (a + b)³ = a³ + b³ + 3ab(a + b)
Method:
According to the question,
x + 1/x = √3
(x + 1/x)³ = x³ + (1/x)³ + 3(x)(1/x) (x + 1/x)
Substitute x + 1/x as √3
→ √3³ = x³ + 1/x³ + 3(√3)
→ 3√3 = x³ + 1/x³ + 3√3
→ 3√3 - 3√3 = x³ + 1/x³
→ x³ + 1/x³ = 0
Hence proved
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