if (x+1/x)^2=3 then show that x^3 + 1/x^3=0
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(X+1/X)²= 3
x+1/x= √3 .......(i)
cube on both sides
(x+1/x)³= (√3 )³
x³+1/x³+3(x+1/x)=3√3
x³+1/x³+3(√3)=3√3 [From( i)=> x+1/x= √3 ]
x³+1/x³+3√3=3√3
x³+1/x³=3√3-3√3
x³+1/x³=0
Hence proved
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