if(x+1/x)^2=3 then value of x^54+x^48+x^42+x^36
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Answer:
4
Step-by-step explanation:
(x+1/x)^2=3
now x^2+1+2x/x^2=3
x^2+2x+1=3x^2
3x^2-x^2-2x-1=0
2x^2-2x-1=0
now factorise
2x^2-2x+x-1=0
2x(x-1)+1(x-1)=0
(x-1)(2x+1)=0
x=1,-1/2
now put x=1
x^54+x^48+x^42+x^36
=1+1+1+1
=4
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