If (x – 1) (x + 2) is the H.C.F. of the polynomials
f(x) = (x2 – 5x + 4) (x2 + ax + b)
and g(x) = (x2 – 3 – 6) (x2 + 3x + b),
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Thus a=3 and b=4
Step-by-step explanation:
(x + 4)(x-2)(x + 1) is the HCF of the polynomials
f(x) = (x² + 2x-8)(x² + 4x + a) and
f(x)=(x+4)(x-2)(x² + 4x + a)
g(x) = (x2 - x-2)(x2 + 3x - b),
g(x) =(x-2)(x+1)(x2 + 3x - b)
common factor here in F(x) and g(x) is (x-2)
But HCF is (x + 4)(x-2)(x + 1)
Thus f(x) and g(x) have (x + 4)(x-2)(x + 1) as common factors
x-2 is already coomon in f and g
and f(x) has already (x+4)
so x² + 4x + a has a factor x+1
or x=-1
putting x=-1
(1)²+4*-1+a=0
1-4+a=0, a=3
similarly in g(x)
x2 + 3x - b has x+4 as a factor
so x=-4
puutingx=-4 we get
(-4)²+3*-4-b=0
16-12-b=0
4-b=0
b=4
Thus a=3 and b=4
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