Question

if x+1÷x=2 then find the value of x^12-1÷x^12​

Answer 1

Answer:

Step-by-step explanation:

x + 1 / x = 2

x^2 + 1 = 2 x

x^2 - 2x + 1 = 0

x^2 - 2( x ) (1) + 1^2= 0

( x - 1 )^2 = 0 = > x - 1 = 0 = > x = 1

∴ ,

x^12 - 1 / x^12 = ( 1 ) ^12 - 1 / ( 1 ) ^12

= 1 - 1 / 1 =( 1 - 1 ) /1 = 0 / 1 = 0

∴ , x^12 - 1 / x^12 = 0

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Your Answer : 0

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Hope it helps.

Answer 2

Answer:

0

Step-by-step explanation:

Eq.1- x+1/x=2

Or,x+1=2x

Or,x-2x=-1

Or,-x= -1

Or,x=1

Eq.2-x^12-1/x^12

Putting the value of x from Eq.1-Eq.2 we get,

1^12-1/1^12

=1-1/1

=1-1

=0

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