Question

If x + (1/x) = 2, then what is the value of x64 + x121?

Answer 1

x+1/x=2 ==> x^2 + 1= 2x ==> (x-1)^2=0 ==>x=1
Then,
64x+121x=185x= 185*1 =185

Answer 2

Answer:

$x^{64}+x^{121}=2$

Step-by-step explanation:

We are given an equation

$x+\frac{1}{x}=2$

Simplify the equation and solve for x

$x^2+1=2x$

$x^2-2x+1=0$

$(x-1)(x-1)=0$

$x-1=0$

$x=1$

We need to find $x^{64}+x^{121}$

Put x=1 into equation

$\Rightarrow 1^{64}+1^{121}$

$\Rightarrow 1+1=2$

$x^{64}+x^{121}=2$