If x+1/x = 2, then x^121+1/x^121 =?
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x +1/x =2
x^2 +1/x^2 =2^2 -2=2
x^3 +1/x^3 =2^3 -3×2=2
(x^2 +1/x^2)(x^3+1/x^3)=2×2
x^5 +1/x + x + 1/x^5= 4
x^5 +1/x^5 =4-2=2
now
(x^3 +1/x^3)(x^3+1/x^3)=2×2
x^6 + 1 + 1 +1/x^6=4
x^6 + 1/x^6=4-2=2
now
(x^6 +1/x^6)(x^5+1/x^5)=2×2
(x^11 + x + 1/x + 1/x^11)=4
x^11 +1/x^11 =4 -2=2
now (x^11 + 1/x^11)(1/x^11 +x^11) =2×2
(x^22+ 1 + 1/x^22 + 1 )=4
x^22 + 1/x^22 =4-2=2
so
x^22+1/x^22 =2
x^2 +1/x^2 =2^2 -2=2
x^3 +1/x^3 =2^3 -3×2=2
(x^2 +1/x^2)(x^3+1/x^3)=2×2
x^5 +1/x + x + 1/x^5= 4
x^5 +1/x^5 =4-2=2
now
(x^3 +1/x^3)(x^3+1/x^3)=2×2
x^6 + 1 + 1 +1/x^6=4
x^6 + 1/x^6=4-2=2
now
(x^6 +1/x^6)(x^5+1/x^5)=2×2
(x^11 + x + 1/x + 1/x^11)=4
x^11 +1/x^11 =4 -2=2
now (x^11 + 1/x^11)(1/x^11 +x^11) =2×2
(x^22+ 1 + 1/x^22 + 1 )=4
x^22 + 1/x^22 =4-2=2
so
x^22+1/x^22 =2
dasaranyak1999p8r4qd:
Tera last wala step bhi to galat h bhai....... x^11 se x^11 multiply hoga to x^22 hota h...... powers get added bro
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