Question

IF ( x - 1/x)^2 = x^2+x+1/x^2 then the value of x is a) -2
b) 2
c) 2x
d) -2×​

Answer 1

Answer:

$\left(x-\dfrac{1}{x}\right)^2=x^2+x+\dfrac{1}{x^2} \\\\\\ \text{Simplifying LHS} \\\\\\ x^2-2+\dfrac{1}{x^2}=x^2+x+\dfrac{1}{x^2} \\\\\\ \text{Combining like terms} \\\\\\ x^2-x^2+\dfrac{1}{x^2} - \dfrac{1}{x^2} -2 = x \\\\\\ -2 = x \\\\\\ \bold{x=-2} \ \ \ \text{Option A} \\\\\\\\ \sf{@rohangupta0424}$