Question

If * (x - 1/x) ^ 2 = x ^ 2 + y + 1/(x ^ 2) then the value of y is

Answer 1

Answer:

We simply substitute x=1,y=2 in the given expression x

2

+y

2

as shown below:

x

2

+y

2

=(1)

2

+(2)

2

=1+4=5

Hence, the value of the expression x

2

+y

2

=5 when x=1,y=2.

Answer 2

Answer:

Y = - 2

Step-by-step explanation:

Let's solve for y.

(x− 1/x)^2 = x^2 +y+1/(x^2)

Step 1: Multiply both sides by x^2.

x^4−2 x^2+1=x^4+x^2 y+1

Step 2: Flip the equation.

x^4 + x^2 y+1 = x^4−2 x^2+1

Step 3: Add -x^4 to both sides.

x^4+x^2 y+1−x^4=x^4−2 x^2+1 −x^4

x^2 y+1 = −2 x^2+1

Step 4: Add -1 to both sides.

x^2 y+1 −1=−2 x^2+1−1

x^2 y= −2 x^2

Step 5: Divide both sides by x^2.

x^2 y /x^2 = - 2 x^2 / x^2

y=−2

Answer:

y=−2