Question

If (x-1) (x- 2) (x- 4) = 0, what are the possible values or x?

Answer 1

Answer:

Possible values of x are 1 , 2 and 4.

Step-by-step explanation:

Given,

( x - 1 )( x - 2 )( x - 4 ) = 0

We know that a product can be 0, if and only when one of term being multiplied is 0.

So, one of the given term must be 0.

Case 1 : If ( x - 1 ) is 0 :

= > x - 1 = 0

= > x = 1

Case 2 : If ( x - 2 ) is 0 :

= > x - 2 = 0

= > x = 2

Case 3 : If ( x - 3 ) is 0 :

= > x - 3 = 0

= > x = 3

Hence the possible values of x are 1 , 2 and 4.

Answer 2

Answer:

The possible values of x are 1,2 and 4.

Step-by-step explanation:

We know,

$(x - 1)(x - 2)(x - 4) = 0....(1)$

We know if product of three terms is 0 then they are separately equal to zero.

So we can write,

$(x - 1) = 0...(2) \\ (x - 2) = 0 ....(3)\\ (x - 4) = 0.....(4)$

From equation (2),

$x - 1 = 0 \\ x = 1$

From equation (3),

$x - 2 = 0 \\ x = 2$

From equation (4),

$x - 4 = 0 \\ x = 4$

This is a problem of Algebra.

Some important Algebra formulas.

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

Know more about Algebra,

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