Question

If x -1/x = 21/10, find the value of x²+ 1/x²​

Answer 1

Answer:

641/100

Step-by-step explanation:

${(x - \frac{1}{x}) }^{2} = {x}^{2} + \frac{1}{ {x}^{2} } - 2$

${( \frac{21}{10} )}^{2} = {x}^{2} + \frac{1}{ {x}^{2} } - 2$

$\frac{441}{100} = {x}^{2} + \frac{1}{ {x}^{2} } - 2$

$\frac{441 + 200}{100} = {x}^{2} + \frac{1}{ {x}^{2} }$

$\frac{641}{100} = {x}^{2} + \frac{1}{ {x}^{2} }$

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