Math, asked by smitikadas2006, 4 months ago

IF x-1 /x =√21 then (x square+1/x square )*(x+1/x) is equal to​

Answers

Answered by dk1789774
5

If x-1/x=√21, then what is the value of (x²+1/x²) (x+1/x) =?

x-1/x=rootof 21 therefore (x-1/x)^2=21

or x^2-2+1/x^2=21 or

x^2 +1/x^2 =23

also x^2 +2+1/x^2 =23+2

or( x+1/x)^2=25 or

x+1/x=5,

x’^2 +1/x^2 =23

therefore (x^2 +1/x^2) (x+1/x)=23*5 or

(x^2 +1/x^2) (x+1/x) =115

Answered by Anonymous
6

Answer:

x-1/x=rootof 21 therefore (x-1/x)^2=21

or x^2-2+1/x^2=21 or

x^2 +1/x^2 =23

also x^2 +2+1/x^2 =23+2

or( x+1/x)^2=25 or

x+1/x=5,

x’^2 +1/x^2 =23

therefore (x^2 +1/x^2) (x+1/x)=23*5 or

(x^2 +1/x^2) (x+1/x) =115

Step-by-step explanation:

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