if x+1/x=22 /7 find the value of x^4+1/x^4
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x^(4+1)/x^4 =x^(4+1-4) = x (Whereas, 1/x^4 =x^-4)
Then,
x+1/x=22/7 or,7x^2+7=22x
or, 7x^2-22x+7=0
then by using shridhor acharjo law
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