if x-1/x=3+2√2 find the value of 1/4(x^3-1/x^3
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Answered by
1
Answer:
108+76√2
Step-by-step explanation:
By solving this we get answer is 108+76√2
Answered by
2
Answer:
GIVEN X-1/X=3+2sqrt2
(X-1/X)^3=(3+2sqrt2)^3
X^3-(1/X)^3-3X×1/X(X-1/X)=27+16sqrt2+3×3×2sqrt2(3+2sqrt2)
X^3-1/X^3-3(X-1/X)=27+16sqrt2+18sqrt2(3+2sqrt2)
X^3-1/X^3-3(3+2sqrt2)=27+70sqrt2+72
X^3-1/X^3-9-6sqrt2=99+70sqrt2
X3-1/X^3=9+99+76sqrt2=108+76sqrt2
THEN 1/4(X^3-1/X^3)=1/4(108+76sqrt2)=27+19sqrt2
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