Math, asked by tedidoh829, 7 months ago

if x-1/x=3+2√2 find the value of 1/4(x^3-1/x^3​

Answers

Answered by mshahzad191110
1

Answer:

108+76√2

Step-by-step explanation:

By solving this we get answer is 108+76√2

Answered by fayazmd4u
2

Answer:

GIVEN X-1/X=3+2sqrt2

(X-1/X)^3=(3+2sqrt2)^3

X^3-(1/X)^3-3X×1/X(X-1/X)=27+16sqrt2+3×3×2sqrt2(3+2sqrt2)

X^3-1/X^3-3(X-1/X)=27+16sqrt2+18sqrt2(3+2sqrt2)

X^3-1/X^3-3(3+2sqrt2)=27+70sqrt2+72

X^3-1/X^3-9-6sqrt2=99+70sqrt2

X3-1/X^3=9+99+76sqrt2=108+76sqrt2

THEN 1/4(X^3-1/X^3)=1/4(108+76sqrt2)=27+19sqrt2

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